Mathématiques

Question

SVP AIDEZ MOI JAI UN DM POUR DEMAIN!!!!!
1/(3x+3)²=9:16
2/9x²+30x+25=0  penser aux identiter remarquable
3/3:2x²+x=0
4/4x+1-(4x+1)(6x+5)=0?

2 Réponse

  • Salut,

    1/

    (3x+3)² = 9/16
    (3x+3)² - 9/16 = 0
    (3x+3)² - (3/4)² = 0
    (3x + 3 - 3/4)(3x+3+3/4) = 0
    (3x + 9/4)(3x + 15/4) = 0

    3x + 9/4 = 0
    3x = -9/4
    x = (-9/4)/3
    x = -3/4

    3x + 15/4 = 0
    3x = -15/4
    x = (-15/4)/3
    x = -5/4


    2/
    9x²+30x+25=0
    (3x)² + 2*5*3x + 5² = 0
    (3x+5)² = 0
    3x + 5 = 0
    3x = -5
    x = -5/3

    3/

    3:2x²+x=0
    x(3/2x + 1) = 0
    x = 0
    3/2x +1=0
    3/2x = -1
    x = -1/(3/2)
    x = -2/3

    4/

    4x+1-(4x+1)(6x+5)=0
    1*(4x+1) - (4x+1)(6x+5) = 0
    (4x+1)[-(6x+5) + 1] = 0
    (4x+1)(-6x-5+1) = 0
    (4x+1)(-6x -4) = 0
    -2(4x+1)(3x + 2) = 0

    4x + 1 = 0

    4x = -1
    x = -1/4

    3x + 2 = 0
    3x = -2
    x = -2/3

    Bonne soirée !



  • 1_ (3x+3)² =9/16------------------- (3x+3)² -(3/4)² =0
    (3x+3+3/4)( 3x+3-3/4)=0
    3x=3/4-3 ou 3x =-3-3/4
           3-12                    -12-3
    3x=------------- ou 3x = --------------------
               4                          4
             -9                  -15
    x=------------  ou x =-------------
           12                    12
    x=-3/4 ou x= -5/4

    2))     9x² +30x+25 =0
     ( 3x+5)² =0  cad 3x+5 =0 cad x =-5/3.

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