Express (1+i) (1-i)^-2 in a+ib from
Mathématiques
sarveshnagvekar13
Question
Express (1+i) (1-i)^-2 in a+ib from
1 Réponse
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1. Réponse jpmorin3
(1+i) (1-i)^-2 =
(1 - i)² = 1 -2i + i² = 1 - 2i - 1 = -2i
(1+i) (1-i)^-2 = (1 + i)/(1 - i)² = (1 + i)/(-2i)
= (-1/2)(1 + i)/i
= (-1/2) ( 1 + i)i / i²
= 1/2 ( i + i²)
=1/2i - 1/2