[tex] \frac{3}{5}x + \frac{4}{7} = \frac{-x}{15} + \frac{3}{2} [/tex] vous pouvez m'aider je n'y arrive pas MERCI

Salut,

[tex] \frac{3}{5}x + \frac{4}{7} = - \frac{1}{15} x + \frac{3}{2} \\ \frac{3}{5}x + \frac{1}{15} x = \frac{3}{2} - \frac{4}{7}\\ \frac{9+1}{15}x = \frac{21-8}{14}\\ \frac{2}{3}x = \frac{13}{14} \\ 2x = \frac{39}{14} \\ x = \frac{39}{28} [/tex]

Bonne soirée !

Bonsoir,

[tex]\dfrac{3}{5}x + \dfrac{4}{7} = \dfrac{-x}{15} + \dfrac{3}{2}\\\\\dfrac{3\times42}{5\times42}x + \dfrac{4\times30}{7\times30} = \dfrac{(-x)\times14}{15\times14} + \dfrac{3\times105}{2\times105}\\\\\dfrac{3\times42}{210}x + \dfrac{4\times30}{210} = \dfrac{(-x)\times14}{210} + \dfrac{3\times105}{210}\\\\126x + 120 = -14x+315\\\\126x+14x =315-120\\\\140x=195\\\\x=\dfrac{195}{140}\\\\x=\dfrac{39\times5}{28\times5}\\\\x=\dfrac{39}{28}[/tex]